SOLUTION: Find and label the vertex and the line of symmetry. Graph the function. f(x) = 1/4x^2 I tried using the solver and nothing computed, but this is the whole problem. I'm stuc

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Find and label the vertex and the line of symmetry. Graph the function. f(x) = 1/4x^2 I tried using the solver and nothing computed, but this is the whole problem. I'm stuc      Log On


   

Question 131783: Find and label the vertex and the line of symmetry. Graph the function.
f(x) = 1/4x^2
I tried using the solver and nothing computed, but this is the whole problem. I'm stuck.
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!
I presume you mean that f%28x%29=%281%2F4%29x%5E2 as opposed to f%28x%29=1%2F%284x%5E2%29.

Given that assumption, you can re-write your equation as:

f%28x%29=%281%2F4%29x%5E2%2B0x%2B0 to put it in the ax%5E2%2Bbx%2Bc form, with a = 1/4, b = 0, and c = 0.

Now recall that the x-coordinate of the parabola vertex is -b%2F2a. In this case: -0%2F%282%281%2F4%29%29=0.

And the y-coordinate of the vertex is at f%280%29=%281%2F4%290%5E2%2B0%2A0%2B0=0.

Now we know that the vertex is at (0,0).

We know that the axis of symmetry is a vertical line that intersects the vertex, so the equation of the axis is x=0