Question 131738: Could you explain to me how to construct the equation of a parabola that has x-axis intercepts at (-2,0) and (4,0) ? Found 2 solutions by solver91311, stanbon:Answer by solver91311(24713) (Show Source):
You can put this solution on YOUR website! If the parabola intercepts the axis at (-2,0), that means the value of the function at x = -2 is f(-2) = 0. Then one of the factors of the equation must be . Likewise, the other factor must be , so the equation becomes:
You can put this solution on YOUR website! Could you explain to me how to construct the equation of a parabola that has x-axis intercepts at (-2,0) and (4,0) ?
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Rule: If "a" is a root, (x-a) is a factor.
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You are given two roots: x = -2 and x=4
So you have two factors (x+2) and (x-4)
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EQUATION:
y = (x+2)(x-4)
y = x^2-2x-8
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Cheers,
Stan H.
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