SOLUTION: Please help me solve for x. I'm having trouble with the radical. f(x)= 3x+3 sq rt x-6

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Question 131657: Please help me solve for x. I'm having trouble with the radical.
f(x)= 3x+3 sq rt x-6
Answer by TakeATuition.com(57) About Me  (Show Source):
You can put this solution on YOUR website!
SOLUTION -
f(x) = 3x%2B3sqrt%28x%29-6
taking sqrt+%28x%29=y
therefore x=y%5E2
we have
3y%5E2%2B3y-6
3y%5E2%2B6y-3y-6
3y%28y%2B2%29-3%28y%2B2%29
%28y%2B2%29%283y-3%29
y%2B2=0
y=-2
3y-3=0
3y=3
y=1
now sqrt+%28x%29=y
substituting the value of y we have
when y=-2
sqrt+%28x%29=-2
x=%28-2%29%5E2
x=4
when y=1
sqrt+%28x%29=1
x=1%5E2
x=1
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