You can put this solution on YOUR website! R^2+3R=5
R^2+3R-5=0
USING THE QUADRATIC EQUATION: R = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}
R=(-3+-SQRT[3^3-4*1*5])/1*2
R=(-3+-SQRT[9-20])/2
R=(-3+-SQRT29)/2
R=(-3+-5.385)/2
R=(-3+5.385)/2
R=2.385/2
R=1.19 ANSWER.
R=(-3-5.385)/2
R=-8.385/2
R=-4.19 ANSWER.