SOLUTION: Find the vertex and line of symmetry {{{f(x)=(x+2)^2}}}

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Question 130754: Find the vertex and line of symmetry

f%28x%29=%28x%2B2%29%5E2
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Since f%28x%29=%28x%2B2%29%5E2 is in vertex form y=a%28x-h%29%5E2%2Bk where a is the stretch/compression factor and (h,k) is the vertex, this means that h=-2 and k=0 (note: f%28x%29=%28x%2B2%29%5E2 really looks like f%28x%29=1%28x-%28-2%29%29%5E2%2B0)


So the vertex is (-2,0)


Also, the line of symmetry is simply the equation x=h. So in this case the line of symmetry is x=-2



If we graph, we can visually verify our answer.


Graph of f%28x%29=%28x%2B2%29%5E2 with a vertex of (-2,0) and the line of symmetry of x=-2