SOLUTION: Solve for x: 8(^2x)+8^x-12=0

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Question 128781: Solve for x:
8(^2x)+8^x-12=0
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
8^(2x)+8^x-12=0
(8^x)^2+8^x-12=0
(8^x+4)(8^x-3)=0 Factor
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8^x-3=0
8^x=3
x=log[8]3
x=.528321
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Let me know if you don't understand any of this.
.
Ed