SOLUTION: Hello I am have difficulty trying to work this one out, your assistance would be greatly appreciated. Ta. I am asked to solve 6(3X-4)^2-7(3X-2)-5=0 using the quadratic equation.

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Hello I am have difficulty trying to work this one out, your assistance would be greatly appreciated. Ta. I am asked to solve 6(3X-4)^2-7(3X-2)-5=0 using the quadratic equation.       Log On


   

Question 128516: Hello
I am have difficulty trying to work this one out, your assistance would be greatly appreciated. Ta.
I am asked to solve 6(3X-4)^2-7(3X-2)-5=0 using the quadratic equation.
The following is what I have tried
6(3X-4)^2-7(3X-2)-5=0
then becomes
6(3X-4)(3X-4)-21X+14-5=0
then becomes
(18X-24)(3X-4)-21X+9=0
then becomes
54X^2-72X-72X+96-21X+9=0
then becomes


54X^2-165X+105=0
This is as far as I could go, and have come to the conclusion that it cannot be done. Can you please confirm this for me, and show me the whys and hows, with an explanation please. Thank you. Cheers D.
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
54x^2-165x+105=0
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x=(165+-sqrt[-165^2-4*54*+105])/2*54
x=(165+-sqrt[27225-22680])/108
x=(165+-sqrt4545])/108
x=(165+-67.42)/108
x=(165+67.42)/108
x=(232.42)/108
x=2.152answer.
x=(165-67.42)/108
x=-97.58/108
x=-.9035 answer.