SOLUTION: Given 3x^2+(k+2)x=-3, determine the value(s) of k so that the equation has real and equal roots.

Algebra ->  Algebra  -> Quadratic Equations and Parabolas -> SOLUTION: Given 3x^2+(k+2)x=-3, determine the value(s) of k so that the equation has real and equal roots.      Log On

Ad: You enter your algebra equation or inequality - Algebrator solves it step-by-step while providing clear explanations. Free on-line demo .
Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!
Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

   

Question 128430: Given 3x^2+(k+2)x=-3, determine the value(s) of k so that the equation has real and equal roots.
Answer by stanbon(57219) About Me  (Show Source):
You can put this solution on YOUR website!
Given 3x^2+(k+2)x=-3, determine the value(s) of k so that the equation has real and equal roots.
----------------
The discriminant must be zero.
b^2-4ac = (k+2)^2-4*3*3 = 0
(k+2)^2 = 36
k+2 = 6 or k+2 = -6
k = 4 or k = -8
==================
Cheers,
Stan H.