SOLUTION: A conservation organization releases 100 animals of an endangered species into a game preserve. The growth of the herd will be modeled by P(t)=1000/19(2.7^-0.1656t), where P is the

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: A conservation organization releases 100 animals of an endangered species into a game preserve. The growth of the herd will be modeled by P(t)=1000/19(2.7^-0.1656t), where P is the      Log On


   

Question 126383: A conservation organization releases 100 animals of an endangered species into a game preserve. The growth of the herd will be modeled by P(t)=1000/19(2.7^-0.1656t), where P is the population of the herd t months after releasing the animals. How many animals are in the herd after one year? Can someone please help me?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
The growth of the herd will be modeled by P(t)=1000/19(2.7^-0.1656t), where P is the population of the herd t months after releasing the animals. How many animals are in the herd after one year?
:
I assume this is the equation:
P(t) = 1000%2F%2819%282.7%5E%28-0.1656t%29%29%29
:
t = 12
:
P(t) = 1000%2F%2819%282.7%5E%28-0.1656%2A12%29%29%29
P(t) = 1000%2F%2819%282.7%5E%28-1.9872%29%29%29
Find 2.7^-1.9872 on good calc
P(t) = 1000%2F%2819%28.138929%29%29
P(t) = 1000%2F2.639657
P(t) = 378.837 ~ 379 animals expected (but do the animals know about this formula?)