Question 124470This question is from textbook Elementary and Intermediate Algebra
: The members of a flying club plan to share equally the cost of $200000 airplane. The members want to find five more people to join the club so that the cost per person will decrease by $2000. How many members are curently in the club?
This question is from textbook Elementary and Intermediate Algebra
Answer by checkley71(8403)   (Show Source):
You can put this solution on YOUR website! (200,000/x)=200,000/(x+5)+2,000
(200,000/x)=(200,000+2,000[x+5])/(x+5)
(200,000/x)=(200,000+2,000x+10,000)/(x+5)
(200,000/x)=(210,000+2,000x)/(x+5)
now cross multiply
200,000(x+5)=(210,000+2,000x)x
200,000x+1,000,000=210,000x+2,000x^2
2,000x^2+210,000x-200,000x-1,000,000=0
2,000x62+10,000x-1,000,000=0
2,000(x^2+5x-500)=0
2,000(x+25)(x-20)=0
x-20=0
x=20 the number of original club members.
proof
200,000/20=(200,000/25)+2000
10,000=8,000+2,000
10,000=10,000
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