Question 124292: Solve the following quadratic equation by completing the square.
2x^2+10x+11=0 Found 3 solutions by jim_thompson5910, edjones, stanbon:Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! 2x^2+10x+11=0
x^2+5x+5.5=0 divide each side by 5.5
x^2+5x+6.25=-5.5+6.25 complete the square by dividing 5 by 2 and suaring the result.
(x+2.5)^2=.75
x+2.5=+-sqrt(.75)
x=-2.5+.866= -1.634
x=-2.5-.866= -3.366
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Ed
You can put this solution on YOUR website! Solve the following quadratic equation by completing the square.
2x^2+10x+11=0
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Divide thru by 2 to get:
x^2+5x+(11/2)=0
Complete the square on the x-terms.
x^2+5x+(5/2)^2 = (-11/2)+(5/2)^2
(x+(5/2))^2 = (-22/4) + (25/4)
(x+(5/2))^2 = 1
x+(5/2) = 1 or x+(5/2)= -1
x = -3/2 or x = -7/2
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Cheers,
Stan H.