SOLUTION: A 4 by 6 inch photograph is to be matted such that the area of the mat is double the area of the photo. Assuming that the mat is the same width all around the picture, what is the

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: A 4 by 6 inch photograph is to be matted such that the area of the mat is double the area of the photo. Assuming that the mat is the same width all around the picture, what is the       Log On


   

Question 123260: A 4 by 6 inch photograph is to be matted such that the area of the mat is double the area of the photo. Assuming that the mat is the same width all around the picture, what is the width of the mat ?
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
THE BEST WAY TO SOLVE THESE TYPE OF PROBLEMS IS TO DRAW A SKETCH ( NOT NECESSARY TO SCALE), ASIGN VALUES FOR THE LENGTH & WIDTH, THEN ADD THE MAT AREA & ASSIGN THE WIDTH=X. YOU'LL GET 4*6=24 FOR THE ORIGINAL PHOTO &
(4+2X)(6+2X)=2+24 OR TWICE THE ORIGINAL AREA.
DOES THIS HELP VISUALIZE THE PROBLEM AND PUT IT IN PERSPECTIVE???????
---------------------------------------------------
2*4*6=(4+2X)(6+2X)
48=24+12X+8X+4X^2
4X^2+20X+24-48=0
4X^2+20X-24=0
4(X^2+5X-6)=0
4(X+6)(X-1)=0
X=1 ANSWER FOR THE WIDTH OF THE MAT.
PROOF
(4+2)(6+2)=48
6*8=48
48=48