SOLUTION: If the value of b^2-4ac is negative, the equation ax^2+bx+c=0. Is there always a real number solution?

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Question 122663: If the value of b^2-4ac is negative, the equation ax^2+bx+c=0. Is there always a real number solution?
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
By definition: if b%5E2-4ac%3C0 (ie if it's negative) then the quadratic will never have real solutions. It will have two complex solutions.