SOLUTION: Algebraically determine the EXACT roots in simplest form for (5/x-3)=(x/x+1)

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Question 122237: Algebraically determine the EXACT roots in simplest form for (5/x-3)=(x/x+1)
Answer by algebrapro18(249) About Me  (Show Source):
You can put this solution on YOUR website!
(5/x-3)=(x/x+1)
5(x+1) = x(x-3)
5x+5 = x^2-3x
0 = x^2-8x-5

a = 1
b = -8
c = -5

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+---> plug values into the quadratic forumla
x+=+%288+%2B-+sqrt%28+%28-8%29%5E2-4%2A1%2A-5+%29%29%2F%282%2A1%29+--->simplify
x=+%288+%2B-+sqrt%2864%2B20%29%29%2F%282%29--->simplify
x=+%288+%2B-+sqrt%2884%29%29%2F%282%29--->simplify sqrt(84)
x=+%288+%2B-+2%2Asqrt%2821%29%29%2F%282%29---> divide by 2
x=+4+%2B-+sqrt%2821%29