SOLUTION: A rocket is launched into the air. The height in feet, of the rocket, above the ground is given by h(t)=-4.9t(squared) + 192t, where t represents the time in seconds after the lau
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-> SOLUTION: A rocket is launched into the air. The height in feet, of the rocket, above the ground is given by h(t)=-4.9t(squared) + 192t, where t represents the time in seconds after the lau
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Question 122161: A rocket is launched into the air. The height in feet, of the rocket, above the ground is given by h(t)=-4.9t(squared) + 192t, where t represents the time in seconds after the launch. (Hint:draw a picture)
#1. How long is the rocket in the air before it reaches the ground?
#2. How long does it take the rocket to reach its highest point?
#3. How high is the rocket at its highest point? I know that to find this answer I use the formula for the line of symmetry, and the vertex is the highest point..I think that it is 19.6 feet if I did it right.
The other questions I do not know how to do.
Thank you! Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! I can plot this
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(1) I need to find the change in when th3e
rocket goes from (t,h) = (0,0) to (t,0) where is the
time to fall back to earth
One solution is This is the point (0,0)
The other solution is sec (this agrees closely with graph)
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(2) The highest point is where when
equation is in the form sec (this is exactly 1/2 the time to hit the ground)
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(3) I need to find when ft (this agrees with graph, also)
