SOLUTION: Joey did an experiment in which he measured the temperature(T) of a cup of hot chocolate, in degrees celcius, with respect to time(t), in minutes. He found that the function T=33(0

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Joey did an experiment in which he measured the temperature(T) of a cup of hot chocolate, in degrees celcius, with respect to time(t), in minutes. He found that the function T=33(0      Log On


   



Question 121714: Joey did an experiment in which he measured the temperature(T) of a cup of hot chocolate, in degrees celcius, with respect to time(t), in minutes. He found that the function T=33(0.28)^t/26 +24 described the relationship. What was the room temperature of the room in which it was placed to cool?
I think it is 24 degrees celcius, does anyone know this one ?

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Joey did an experiment in which he measured the temperature(T) of a cup of hot chocolate, in degrees celcius, with respect to time(t), in minutes. He found that the function T=33(0.28)^t/26 +24 described the relationship. What was the room temperature of the room in which it was placed to cool?
I think it is 24 degrees celcius, does anyone know this one ?
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Find T(0) to get the starting temperature
find T(some very large number) to get the temperature after
the cup has cooled a very large time.
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As t get's larger and larger (0.28)^t gets closer and closer to
zero.
So as t get's larger and larger T get's closer and closer to 24.
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I think you are right.
Cheers,
Stan H.