Question 121713: What is the correct mapping rule to show the transformation of y=2^x for the equation 1/4(y-5)=2^2x-3 ? Can someone please help, I've been stuck for a few days on this one.I'm guessing: (x,y)-(x+3),(4y+5), anyone know?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! What is the correct mapping rule to show the transformation of y=2^x for the equation 1/4(y-5)=2^2x-3 ? Can someone please help, I've been stuck for a few days on this one.I'm guessing: (x,y)-(x+3),(4y+5), anyone know?
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Rearranging I get:
y = 4*(2^(2x-3)-3)+5
y = 4*2^(2x-3)+7
Not sure about this one, but:
It looks to me like y=2^x is moved (3/2)to the right, up 7, and "stretched"
by a factor of 4.
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Maybe (x,y)----(x-(3/2),4y+7)
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What do you think?
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Cheers,
Stan H.
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