SOLUTION: The fromula A=30(0.46)^t describes the amount of ASA in a typical patient's bloodstream in mg/cm^3 in terms of the time t in hours after the peak dosage.Make a table of values and

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: The fromula A=30(0.46)^t describes the amount of ASA in a typical patient's bloodstream in mg/cm^3 in terms of the time t in hours after the peak dosage.Make a table of values and       Log On


   



Question 121511: The fromula A=30(0.46)^t describes the amount of ASA in a typical patient's bloodstream in mg/cm^3 in terms of the time t in hours after the peak dosage.Make a table of values and draw the graph of this function. Can someone please help me ???
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
The formula A=30(0.46)^t describes the amount of ASA in a typical patient's bloodstream in mg/cm^3 in terms of the time t in hours after the peak dosage.Make a table of values and draw the graph of this function.
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Let's make a table starting with t = 0 which is the peak dosage
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In the formula substitute 0, for t and find the ASA
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A = 30(.46)^0
We know that any number with an exponent of 0 is = 1,
A = 30 * 1
A = 30, (which is what you would expect)
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The first value in the table> (When t = 0; A = 20)
t | A
-------
0 | 30
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Find A when t = 1
A = 30(0.46)^1
A = 30 * 0.46
A = 13.8
Continuing our table ( When t = 1; A = 13.8)
t | A
-------
0 | 30
1 | 13.8
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Find A when t = 2
A = 30(0.46)^2
A = 30 * .2116; found (.46^2 with a calculator)
A = 6.348
Continuing our table
t | A
-------
0 | 30
1 | 13.8
2 | 6.348
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You should be getting the idea, I going to jump to when t = 6 hrs
You can fill in the values for 3, 4, 5, just like we just did;
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A = 30(0.46)^6
A = 30 * .0095 (.46^6 on a calculator again)
A = .284, almost gone, would you say?)
t | A
-------
0 | 30
1 | 13.8
2 | 6.348
3 |_____
4 |_____
5 |_____
6 | .284
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They want you to graph these values. Everything is positive
Let y axis be A and the x axis be t
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The scale will be y: 0 to 32, x: 0 to 8
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If you plot the above values as x/y coordinates, your graph should look like this
+graph%28+300%2C+200%2C+-4%2C+8%2C+-10%2C+32%2C+30%28.46%29%5Ex%29+
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By looking at this graph you can see approximately what amt is left in the bloodstream after so many hrs.
Check to see if it agrees with the values you calculated for 3, 4 and 5.
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Did I explain this so you know what's going on here? Let me know.
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So sorry about this mistake, it changed things though out the problem, please
check everything again. A