SOLUTION: Using the following sequence,determine what type of function describes the sequence. Once you determine the type of function,find the function algebraically.(4,9,17,28,42,59,...)

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Question 120780: Using the following sequence,determine what type of function describes the sequence. Once you determine the type of function,find the function algebraically.(4,9,17,28,42,59,...)
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let's look at each consecutive pair and how you get from the first number to the second number.
4-9: +5
9-17: +8
17-28: +11
28-42: +14
42-59: +17
Looks like you add 3 to the difference from the previous pair.
The next pair would look like this,
59-?: +20
59+20=79.
The next number is 79.
Now the pattern.
4-9: 5= 1*5
4-17: 13 = 5 + (5+3) = 2*5 + 3
4-28: 24 = 5 + (5+3) + (5+3+3) = 3*5 + 3*3
4-42: 38 = 5 + (5+3) + (5+3+3) + (5+3+3+3)=4*5+6*3
4-59: 55 = 5 + (5+3) + (5+3+3) + (5+3+3+3) + (5+3+3+3+3) =5*5+10*3
4-79: 66 = 5 + (5+3) + (5+3+3) + (5+3+3+3) + (5+3+3+3+3) + (5+3+3+3+3+3)=6*5+15*3
The formula for the nth term would look like
a%5Bn%5D=4%2B%28n-1%29%2A5+%2B++3%2Asum%28+n-1%2C+0%2C+n-1+%29
You can simplify the sum term since
sum%28+n-1%2C+0%2C+n-1+%29=%28%28n-1%29%28n-2%29%29%2F2
Since we have n-2, this simplification only applies for n>1.
For n=1, the sum equals zero.
a%5B1%5D=4%2B%281-1%29%2A5+%2B++0
a%5B1%5D=4
Therefore
a%5Bn%5D=4%2B%28n-1%29%2A5+%2B++3%2A%28%28n-1%29%28n-2%29%29%2F2
a%5Bn%5D=4%2B%28n-1%29%2A%285+%2B++3%2A%28n-2%29%2F2%29 for n>1
and
a%5B1%5D=4
Check the answer with a couple of points to make sure everything looks good.
2nd term : n=2
a%5Bn%5D=4%2B%28n-1%29%2A%285+%2B++3%2A%28n-2%29%2F2%29
a%5Bn%5D=4%2B%282-1%29%2A%285+%2B++3%2A%282-2%29%2F2%29
a%5Bn%5D=4%2B%281%29%2A%285%29
a%5B2%5D=9
5th term : n=5
a%5Bn%5D=4%2B%28n-1%29%2A%285+%2B++3%2A%285-2%29%2F2%29
a%5B5%5D=4%2B%284%29%2A%285+%2B++3%2A%283%29%2F2%29
a%5B5%5D=4%2B%284%29%2A%2819%2F2%29
a%5B5%5D=4%2B%2838%29
a%5B5%5D=42
The asnwers check out to the originals.