SOLUTION: What are the EXACT values of the roots of the quadratic equation 1/2(x^2-6x)=2 ?

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Question 120474: What are the EXACT values of the roots of the quadratic equation 1/2(x^2-6x)=2 ?
Answer by stanbon(57250) About Me  (Show Source):
You can put this solution on YOUR website!
What are the EXACT values of the roots of the quadratic equation
1/2(x^2-6x)=2 ?
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x^2-6x = 4
x^2-6x-4 = 0
x = [6 +- sqrt(36-4*-4)]/2
x = [6 +- sqrt(52)]/2
x = [6 +- 2sqrt(13)]/2
x = 3+sqrt(13) or x = 3-sqrt(13)
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Cheers,
Stan H.