SOLUTION: Last year at East High School, a survey showed that 79 students played soccer or basketball, 30 played soccer, and 14 played both.
How many of the students played basketbal
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-> SOLUTION: Last year at East High School, a survey showed that 79 students played soccer or basketball, 30 played soccer, and 14 played both.
How many of the students played basketbal
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Question 1203879: Last year at East High School, a survey showed that 79 students played soccer or basketball, 30 played soccer, and 14 played both.
How many of the students played basketball?
i know the answer is 63 due to getting the problem incorrect but how would i go ahead and solve this problem? Found 2 solutions by MathLover1, ikleyn:Answer by MathLover1(20849) (Show Source):
You can put this solution on YOUR website! students played soccer or basketball,
played soccer, and played both
if so, then played soccer only
since students played soccer or basketball, then played basketball only
so, we have
How many of the students played basketball?
look at set B only
30 played S
14 played both
79 played S or B
For the union of two sets, S (soccer) and B (basketball), we write
n(S U B) = n(S) + n(B) - n(S and B)
and substitute there given quantities
79 = 30 + n(B) - 14.
From this equation, we find the unknown amount
n(B) = 79 -30 + 14 = 63.
Thus the answer is: 63 students play basketball.
