SOLUTION: A quadratic polynomial of the form y=x^2+bx+c has x-intercepts at x=-1 and x=-10. Find the coefficients of b and c. If anyone is able to help me solve this, I would appreciate i

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: A quadratic polynomial of the form y=x^2+bx+c has x-intercepts at x=-1 and x=-10. Find the coefficients of b and c. If anyone is able to help me solve this, I would appreciate i      Log On


   

Question 1200623: A quadratic polynomial of the form y=x^2+bx+c has x-intercepts at x=-1 and x=-10. Find the coefficients of b and c.
If anyone is able to help me solve this, I would appreciate it :)
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.

The roots of the polynomial are -1 and -10 (given).


Hence, due to Vieta's theorem, the coefficient "b" is the sum of the roots
with the opposite sign

    b = -((-1) + (-10)) = -(-11) = 11.


Due to Vieta's theorem, the coefficient "c" is the product of the roots

    c = (-1)*(-10) = 10.


ANSWER.  b = 11;  c = 10.

Solved.