SOLUTION: What is the range for 3(y+2)= (x-4)^2?

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Question 119666: What is the range for 3(y+2)= (x-4)^2?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
3%28y%2B2%29=%28x-4%29%5E2
%28y%2B2%29=%281%2F3%29%2A%28x-4%29%5E2
y=-2%2B%281%2F3%29%2A%28x-4%29%5E2
Since the second term is always positive, y will never be less than -2.
The range is therefore,
y%3E=-2
+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+-2%2B%281%2F3%29%2A%28x-4%29%5E2%29+