SOLUTION: Solve: 4(x-5)^2=-32 I got x=5=+- 2isqrt2 but I'm not sure if I am doing this correctly :)

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Question 119298: Solve: 4(x-5)^2=-32 I got x=5=+- 2isqrt2 but I'm not sure if I am doing this correctly :)
Found 2 solutions by Fombitz, MaxLiebling:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
x=5+%2B-+2sqrt%282%29i is correct.
You can always check your answer.
4%28x-5%29%5E2=-32
4%285+%2B-+2sqrt%282%29i-5%29%5E2=-32
4%282sqrt%282%29i%29%5E2=-32
-32=-32
True statement.
Correct answer.

Answer by MaxLiebling(13) About Me  (Show Source):
You can put this solution on YOUR website!
I got the same result:
4 * (x-5)^2 = -32
(x-5)^2 = -8
x-5 = +/-2i * sqrt(2)
x = 5 +/-2i * sqrt(2)
proof:
4 * (x-5)^2 =
4 * ([5 +/-2i * sqrt(2)] - 5)^2 =
4 * (+/-2i * sqrt(2))^2 =
4 * (+/-2)^2 * i^2 * sqrt(2)^2 =
4 * 4 * -1 * 2 = -32