SOLUTION: The height h in feet of an object after t seconds is given by the function h = -16t^2 + 40t + 10. How high was the object when it was launched?

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: The height h in feet of an object after t seconds is given by the function h = -16t^2 + 40t + 10. How high was the object when it was launched?      Log On

The initial height is the value of the function h(t) at t = 0


    h(0) = -16*0^2 + 40*0 + 10 = 0 + 0 + 10 = 10.


ANSWER.  Initial height is 10 feet.