SOLUTION: What is the transformational form of y= -1/3x^2+3x-1 ? I got -3(y+23/4) =(x+9/2)^2 It was marked wrong :(

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: What is the transformational form of y= -1/3x^2+3x-1 ? I got -3(y+23/4) =(x+9/2)^2 It was marked wrong :(      Log On


   

Question 118443: What is the transformational form of y= -1/3x^2+3x-1 ?
I got -3(y+23/4) =(x+9/2)^2 It was marked wrong :(
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
given:
y=+-%281%2F3%29x%5E2%2B3x-1
Find: Transformational Form
%281%2Fa%29%28y+-+k%29+=+%28x+-+h%29%5E2

Since Standard Form is:
y+=+a%28x-h%292%2Bk
Where (h and k) are vertex coordinates, we will find vertex first:


Solved by pluggable solver: Completing the Square to Get a Quadratic into Vertex Form

Error: the leading coefficient "a" cannot be equal to zero.




Transformational Form ,
%281%2Fa%29%28y+-+k%29+=+%28x+-+h%29%5E2
Since a+=+-1%2F3
h+=9%2F2+}
k+=+23%2F4
then
1%2F%28-1%2F3%29%28y+-+23%2F4%29+=+%28x+-+9%2F2%29%5E2
%28-3%29%28y+-+23%2F4%29+=+%28x+-+9%2F2%29%5E2