SOLUTION: the intensity I of illumination from a light source is inversely proportional to the square of the distance d from the source. Suppose the intensity is 320 candela at a distance o
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Question 1173968: the intensity I of illumination from a light source is inversely proportional to the square of the distance d from the source. Suppose the intensity is 320 candela at a distance of 10 feet from a light source.
a. What is the intensity at 2 feet from the source?
b. How far away from the source will the intensity be 400 candela?
a. the intensity of illumination is ____ at a distance of 2 feet from the source. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! the intensity I of illumination from a light source is inversely proportional to the square of the distance d from the source.
make an equation from this information given
I = where
I=illumination in candelas;
d=distance from light source,
k=constant
:
Suppose the intensity is 320 candela at a distance of 10 feet from a light source.
Find k with these values = 320
k = 320 * 100
k = 32000
:
a. What is the intensity at 2 feet from the source?
I =
I = 8000 candelas
:
b. How far away from the source will the intensity be 400 candela?
400 =
400d^2 = 32000
d^2 =
d^2 = 80
d =
d = 8.9 ft
:
