SOLUTION: Please help me solve this quadratic equation and round the answer to the nearest hundredth I also need to know the correct "form." I'm new to quadratic equations and am struggli

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Question 1173107: Please help me solve this quadratic equation and round the answer to the nearest hundredth
I also need to know the correct "form." I'm new to quadratic equations and am struggling
form options
(x+[])^2=[] or (x-[])^2=[]
equation:
x^2+6x+7=0

Found 4 solutions by Boreal, Edwin McCravy, MathTherapy, ikleyn:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
x^2+6x+7=0
can complete the square
x^2+6x=-7 first step. Completing the square is taking half of the coefficient of the first power term (3), and squaring it, (9), adding it to both sides
x^2+6x+9=-7+9=2
now the left side is a perfect square
(x+3)^2=2
Take the square root of both sides
x+3=sqrt (2) and x+3=- sqrt(2)
x=-3 +sqrt(2) and x= -3- sqrt (2)
sqrt(2)=1.414
so x=-1.59 and x=-4.41
can check using the quadratic formula, which gives the same result
graph%28300%2C300%2C-5%2C5%2C-5%2C5%2Cx%5E2%2B6x%2B7%29

Answer by Edwin McCravy(20055) About Me  (Show Source):
You can put this solution on YOUR website!
  
Looks like you're studying "completing the square".

x2 + 6x + 7 = 0

That won't factor, so we must "MAKE IT FACTOR IN A SPECIAL WAY!!!"

Subtract 7 from both sides, leaving only the two terms with x on the left.

x2 + 6x     = -7

Now we need to add something to both sides that will make the left side
factor in a SPECIAL way.

Here is the rule:
                    1. Multiply the coefficient of x by 1/2.
                       [That is, 6 times 1/2 gives 3.]
                    2. Square what you get.
                       [We square 3 getting 9.]
                    3. Add that to both sides of the equation.
                       [We add 9 to both sides of the equation:

x2 + 6x + 9 = -7 + 9

We factor the left side, and combine the numbers on the right.

(x + 3)(x + 3) = 2

Notice that this factored in a SPECIAL way, because both factors
are the same, (x + 3).  So we can write the left side as (x + 3)2.

      (x + 3)2 = 2

Now we can take the square roots of both sides.   Since every number has
two square roots we must annex a ± to the right side when we take the
square roots of both sides:

      sqrt%28%28x%2B3%29%5E2%29%22%22=%22%22%22%22+%2B-+sqrt%282%29

When we take the square root of something squared, we just take away the
square root symbol and the square.

       x%2B3%22%22=%22%22%22%22+%2B-+sqrt%282%29

Then we add -3 to both sides of the equation:

        x%22%22=%22%22-3+%2B-+sqrt%282%29

So there are two solutions: -3%2Bsqrt%282%29 and -3-sqrt%282%29

Checking the first solution with a calculator:

-3+sqrt(2) = -1.585786438

Substituting that for x

x%5E2%2B6x%2B7%22%22=%22%220
%28-1.585786438%29%5E2%2B6%28-1.585786438%29%2B7%22%22=%22%220
2.514718626-9.514718628%2B7%22%22=%22%220
-2E-9%22%22=%22%220

That -2E-9 means scientific notation -2 x 10-9
which means -0.000000002.

So it means that since all calculators are limited in the number of
decimal places they can handle, we accept that as close enough to 0.

We can check the other solution in the same way.

Edwin


Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

Please help me solve this quadratic equation and round the answer to the nearest hundredth
I also need to know the correct "form." I'm new to quadratic equations and am struggling
form options
(x+[])^2=[] or (x-[])^2=[]
equation:
x^2+6x+7 = 0


matrix%281%2C3%2C+x%5E2+%2B+6x+%2B+7%2C+%22=%22%2C+0%29
---- Taking matrix%281%2C3%2C+1%2F2%2C+of%2C+b%29, squaring it, and then ADDING the result to both sides



matrix%281%2C3%2C+sqrt%28%28x+%2B+3%29%5E2%29%2C+%22=%22%2C+%22%22%2B-sqrt%282%29%29 ----- Taking square root of both sides
matrix%281%2C3%2C+x+%2B+3%2C+%22=%22%2C+%22%22%2B-sqrt%282%29%29
matrix%281%2C3%2C+x%2C+%22=%22%2C+%22%22%2B-sqrt%282%29+-+3%29 ------ Subtracting 3 from both sides

Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.

See my solution under this link

https://www.algebra.com/algebra/homework/quadratic/Quadratic_Equations.faq.question.1173138.html

https://www.algebra.com/algebra/homework/quadratic/Quadratic_Equations.faq.question.1173138.html


' ' ' ' ' ' ' ' ' ' ' ' ' ' ' ' '

In this site, you have a bunch of lessons on solving quadratic equations:
    - Introduction into Quadratic Equations
    - PROOF of quadratic formula by completing the square
    - HOW TO complete the square - Learning by examples
    - HOW TO solve quadratic equation by completing the square - Learning by examples
    - Solving quadratic equations without quadratic formula
    - Who is who in quadratic equations
    - Using Vieta's theorem to solve qudratic equations and related problems
    - Using quadratic equations to solve word problems
    - Challenging word problems solved using quadratic equations
    - HOW TO solve the problem on quadratic equation mentally and avoid boring calculations
    - OVERVIEW of lessons on solving quadratic equations

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The referred lessons are the part of this textbook under the topic  "Quadratic equations".


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