SOLUTION: The length of a rectangular garden is two feet less than three times the width. If the area is 65ft², find the dimension. Pls answer my question

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Question 1170662: The length of a rectangular garden is two feet less than three times the width. If the area is 65ft², find the dimension.
Pls answer my question
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!

if the length L of a rectangular garden is two feet less than three times the width W , we have
L=3W-2 ....eq.1
if the area is 65ft%5E2%2C+we+have%0D%0A%0D%0A%7B%7B%7BL%2AW=65....eq.2
substitute L from eq.1
%283W-2%29%2AW=65....solve for W
3W%5E2-2W=65
3W%5E2-2W-65=0....factor
3W%5E2%2B13W-15W-65=0
%283W%5E2-15W%29%2B%2813W-65%29=0
3W%28W-5%29%2B13%28W-5%29=0
%28W+-+5%29+%283W+%2B+13%29+=+0
use only positive solution
->%28W+-+5%29+=+0=>W=5
go to eq.1
L=3W-2 ....eq.1, substitute W
L=3%2A5-2
L=13
dimension:
the length of a rectangular garden is 13ft
the width of a rectangular garden is 5ft