SOLUTION: An athletic store sells about 200 pairs of basketball shoes per month when it charges $120 per pair. For each $2 increase in price, the store sells two fewer pairs of shoes. How mu

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Question 1169633: An athletic store sells about 200 pairs of basketball shoes per month when it charges $120 per pair. For each $2 increase in price, the store sells two fewer pairs of shoes. How much should the store charge to maximize monthly revenue? What is the maximum monthly revenue?
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617) (Show Source):
You can put this solution on YOUR website!

PRICE QUANTITY SOLD REVENUE 120 200 120+2 200-2 120+4 200-4 . . 120+x 200-x (120+x)(200-x)

R for Revenue,

Find the zeros of R. In the exact middle will be the x value for maximum revenue.

120+x=0,...
and then
200-x=0,...
and then find the exact middle value.

Maximum R when x is 40.
This corresponds to price dollar per pair, for maximum revenue of dollars.

Answer by MathTherapy(10552) (Show Source):
You can put this solution on YOUR website!
An athletic store sells about 200 pairs of basketball shoes per month when it charges $120 per pair. For each $2 increase in price, the store sells two fewer pairs of shoes. How much should the store charge to maximize monthly revenue? What is the maximum monthly revenue?

The other person makes so, so many MISTAKES, so this is another one of his responses that you need to IGNORE!!
His equation: MAY get you ONE correct answer (for some STRANGE reason), but not both!
Therefore, .