SOLUTION: "For what values of k will the equation x^2 + kx + 25 = 0 have no real solution?"

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Question 1166004: "For what values of k will the equation x^2 + kx + 25 = 0 have no real solution?"
Answer by ikleyn(52779) About Me  (Show Source):
You can put this solution on YOUR website!
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A necessary and sufficient condition is negativity of the discriminant of the equation


    b^2 - 4ac < 0,   or  k^2 - 4*25 < 0,   or  k^2 < 100.


So, in the interval  -10 < k < 10,  the given quadratic equation has no real roots.

Solved.