SOLUTION: In preparation for a party, Heather fills a large jar with gum drops. Before the party begins, Michael see the gum drop jar. He (hoping that no one will realize) takes one-third of

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: In preparation for a party, Heather fills a large jar with gum drops. Before the party begins, Michael see the gum drop jar. He (hoping that no one will realize) takes one-third of      Log On


   



Question 11602: In preparation for a party, Heather fills a large jar with gum drops. Before the party begins, Michael see the gum drop jar. He (hoping that no one will realize) takes one-third of the drops. Soon after, Tanya takes one-third of the gum drops (she too hopes that nobody will notice). Finally, Brian appears and, like the others, takes one-third of the gum drops. If forty gum drops are left in the jar, how many did it originally contain?
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = the original number of jelly beans in the jar before the pilfering began.
After Michael has pinched his third, the number left is:
x+-+%281%2F3%29x+=+%282%2F3%29x
After Tanya's sampling, the number left is:
%282%2F3%29x+-+%281%2F3%29%282%2F3%29x+=+%286%2F9%29x+-+%282%2F9%29x = %284%2F9%29x
Finally, after Brian has helped himself to one third, there are 40 jelly beans remaining:
%284%2F9%29x+-+%281%2F3%29%284%2F9%29x+=+%2812%2F27%29x+-+%284%2F27%29x
%288%2F27%29x+=+40 Multiply both sides by 27.
8x+=+1080 Divide both sides by 8.
x+=+135 There were 135 jelly beans in the jar before the crime.
Check:
135+-+135%2F3+=+135+-+45 = 90
90+-+90%2F3+=+90+-+30 = 60
60+-+60%2F3+=+60+-+20 = 40