SOLUTION: A teacher can sell 123 of her pies at $4 per pie. for each $0.50 decreases in price she can sell 20 additional pies
write a quadratic equation
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-> SOLUTION: A teacher can sell 123 of her pies at $4 per pie. for each $0.50 decreases in price she can sell 20 additional pies
write a quadratic equation
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Question 1159510: A teacher can sell 123 of her pies at $4 per pie. for each $0.50 decreases in price she can sell 20 additional pies
write a quadratic equation Answer by Boreal(15235) (Show Source):
You can put this solution on YOUR website! Revenue= 123*$4
for pie sale of $3.50 per pie, she can sell 143
so for sale price of $4-(0.50x) the number of pies is 123+20x
that product is the revenue or 492+80x-61.5x-10x^2
so the quadratic is revenue(x)= -10x^2+18.5x+492
