SOLUTION: A Square has its length increased by 6 feet and it’s with by 8 feet. If the resulting rectangle has an area of 239.25 ft.² what was the perimeter of the original square

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: A Square has its length increased by 6 feet and it’s with by 8 feet. If the resulting rectangle has an area of 239.25 ft.² what was the perimeter of the original square      Log On


   

Question 1156268: A Square has its length increased by 6 feet and it’s with by 8 feet. If the resulting rectangle has an area of 239.25 ft.² what was the perimeter of the original square
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
x by x, the original square
Area x%5E2.


Increased:
Area now %28x%2B6%29%28x%2B8%29=239.25
x%5E2%2B14x%2B48-239.25=0
x%5E2%2B14x-191.25=0
x=%28-14%2Bsqrt%28196%2B4%2A191.25%29%29%2F2
x=%28-14%2B31%29%2F2
highlight_green%28x=8.5%29
The question asks for the sum of four of these.
Perimeter of original square, 34 feet.