SOLUTION: A model rocket is launched with an initial velocity of 170 ft/s. The height, h, of the rocket t seconds after launch is given by
h = −16t2 + 170t
. How many seconds after the
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-> SOLUTION: A model rocket is launched with an initial velocity of 170 ft/s. The height, h, of the rocket t seconds after launch is given by
h = −16t2 + 170t
. How many seconds after the
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Question 1154815: A model rocket is launched with an initial velocity of 170 ft/s. The height, h, of the rocket t seconds after launch is given by
h = −16t2 + 170t
. How many seconds after the launch will the rocket be 314 ft above the ground? Round to the nearest hundredth. Answer by ikleyn(52780) (Show Source):
To get the answer, solve the quadratic equation
-16t^2 + 170t = 314.
You will get 2 roots.
One root is the solution for the model moving up, while the other root is the solution for the model falling down.
