SOLUTION: . You can model the arch of a building entrance by using the y=(-1/3)(x+6)(x-6), where x and y are measured in feet. The x-axis represents the ground, find the width of the arch at

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: . You can model the arch of a building entrance by using the y=(-1/3)(x+6)(x-6), where x and y are measured in feet. The x-axis represents the ground, find the width of the arch at      Log On


   

Question 1154264: . You can model the arch of a building entrance by using the y=(-1/3)(x+6)(x-6), where x and y are measured in feet. The x-axis represents the ground, find the width of the arch at the ground. *
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


The given form of the function tells you the x-intercepts are at -6 feet and +6 feet, so the arch is 12 feet wide at the ground.