SOLUTION: How far will an object fall in 5 seconds if it is thrown downward at an initial velocity of 30m/sec from a height of 200 m?

The general formula to find the distance for such a move is


    d(t) =  + ,


where "g" is the free fall acceleration  (9.81 m^2/s; sometimes the value of 10 m^2/s is used), and  is the initial velocity
(30 m/s, in this case).



So, substitute the numbers into the formula and calculate


    d(5) =  + 30*5 = 275 meters.


Compare it with the given height of 200 meters.


It should be clear to you that the body will reach the Earth surface for lesser time than 5 seconds.


So, "how far" in this case is 200 m.    ANSWER