SOLUTION: Solve using the quadratic formula: x2 – 3x – 23 = 5
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-> SOLUTION: Solve using the quadratic formula: x2 – 3x – 23 = 5
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Question 113753
:
Solve using the quadratic formula:
x2 – 3x – 23 = 5
Found 2 solutions by
checkley71, jim_thompson5910
:
Answer by
checkley71(8403)
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X^2-3X-23=5
X^2-3X-23-5=0
X^2-3X-28=0
X=(3+-SQRT[(3^2-4*1*-28])/281
X=(3+-SQRT9+112)/2
X=(3+-SQRT121)/2
X=(3+-11)/2
X=(3+11)/2
X=14/2
X=7 ANSWER.
X=(3-11)/2
X=-8/2
X=-4 ANSWER.
Answer by
jim_thompson5910(35256)
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You can
put this solution on YOUR website!
Start with the given equation
Subtract 5 from both sides
Let's use the quadratic formula to solve for x:
Starting with the general quadratic
the general solution using the quadratic equation is:
So lets solve
( notice
,
, and
)
Plug in a=1, b=-3, and c=-28
Negate -3 to get 3
Square -3 to get 9 (note: remember when you square -3, you must square the negative as well. This is because
.)
Multiply
to get
Combine like terms in the radicand (everything under the square root)
Simplify the square root (note: If you need help with simplifying the square root, check out this
solver
)
Multiply 2 and 1 to get 2
So now the expression breaks down into two parts
or
Lets look at the first part:
Add the terms in the numerator
Divide
So one answer is
Now lets look at the second part:
Subtract the terms in the numerator
Divide
So another answer is
So our solutions are:
or
Notice when we graph
, we get:
and we can see that the roots are
and
. This verifies our answer