SOLUTION: The solubility equilibrium constant for the dissolution of copper (I) chloride into copper ions and chlorine ion is Ksp = [Cu+][Cl-]. If the solubility constant is Ksp = 1.7 × 1

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: The solubility equilibrium constant for the dissolution of copper (I) chloride into copper ions and chlorine ion is Ksp = [Cu+][Cl-]. If the solubility constant is Ksp = 1.7 × 1      Log On


   

Question 1130327: The solubility equilibrium constant for the dissolution of copper (I) chloride into copper ions and chlorine ion is Ksp = [Cu+][Cl-].
If the solubility constant is Ksp = 1.7 × 10-7, and the concentration of chlorine (Cl-) is 0.2 mol/L greater that the concentration of copper (Cu+), what is the concentration of copper ions in solution? Round your answer to 2 significant figures.
The concentration of copper ions in solution is
Found 2 solutions by ikleyn, josgarithmetic:
Answer by ikleyn(52778) About Me  (Show Source):
You can put this solution on YOUR website!
.
Go directly to some Chemistry site helping students, and post your question/problem there.

Good luck !



Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
Let x be [Cu%5E%28%2B1%29] and therefore x+0.2 is the [Cl%5E%28-1%29] concentration.

Ksp=1.7%2A10%5E%28-7%29, given

x%28x%2B0.2%29=1.7%2A10%5E%28-7%29
Solve for x.