SOLUTION: A dog trainer has 108 ft of fencing that will be used to create a rectangular work area for dogs. If the trainer wants to enclose an area of 560 ft2, what will be the dimensions of

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: A dog trainer has 108 ft of fencing that will be used to create a rectangular work area for dogs. If the trainer wants to enclose an area of 560 ft2, what will be the dimensions of      Log On


   

Question 1126420: A dog trainer has 108 ft of fencing that will be used to create a rectangular work area for dogs. If the trainer wants to enclose an area of 560 ft2, what will be the dimensions of the work area?
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
system%28x%2By=54%2Cxy=560%29

x%2854-x%29=560


-x%5E2%2B54x=560
-x%5E2%2B54x-560=0
x%5E2-54x%2B560=0
discriminant 54%5E2-4%2A560=676=26%5E2
x=%2854%2B-+26%29%2F2
x=27%2B-+13
system%28x=14%2Cor%2Cx=40%29


In fact the dimensions should be length 40 and width 14.

check: 14+40=54
and
14*40=560