SOLUTION: For the following demand equation, find the largest possible revenue. q = -2p + 1,000 a. 375,000 b. 250 c. 250,000 d. 125,000 e. 500

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: For the following demand equation, find the largest possible revenue. q = -2p + 1,000 a. 375,000 b. 250 c. 250,000 d. 125,000 e. 500      Log On


   

Question 1118523: For the following demand equation, find the largest possible revenue.
q = -2p + 1,000
a. 375,000
b. 250
c. 250,000
d. 125,000
e. 500
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


The revenue is pq+=+-2p%5E2%2B1000p.

The maximum revenue is when p+=+-b%2F2a+=+-1000%2F-4+=+250.

The revenue when p = 250 is -2%28250%5E2%29%2B1000%28250%29+=+125000.

Answer d.