SOLUTION: The area of the rubber coating for a flat roof was 96 ft^2. The rectangular frame the carpenter built for the flat roof has dimensions such that the length us 4 feet longer than th

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: The area of the rubber coating for a flat roof was 96 ft^2. The rectangular frame the carpenter built for the flat roof has dimensions such that the length us 4 feet longer than th      Log On


   



Question 1116774: The area of the rubber coating for a flat roof was 96 ft^2. The rectangular frame the carpenter built for the flat roof has dimensions such that the length us 4 feet longer than the width. What are the dimensions of the frame?
Found 2 solutions by Alan3354, josgarithmetic:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The area of the rubber coating for a flat roof was 96 ft^2. The rectangular frame the carpenter built for the flat roof has dimensions such that the length us 4 feet longer than the width. What are the dimensions of the frame?
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Find a pair of factors of 96 that differ by 4.
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1*96 NG
2*48 NG
etc

Answer by josgarithmetic(39615) About Me  (Show Source):
You can put this solution on YOUR website!
w, width
w+4, length

w%28w%2B4%29=96
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Simple arithmetic knowledge possible - find two factors of 96 which differ by 4. Look at list of all combinations of two factors.


Otherwise, the another way can be this:
w%5E2%2B4w-96=0
%28w-8%29%28w%2B12%29=0
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system%28w=8%2Cand%2Cw%2B4=12%29

Length 12
Width 8