SOLUTION: The vertex of a parabola is (-2, -20), and its y-intercept is (0, -12). The equation of the parabola is y = __x^2+__x+__

We draw the approximate graph, using what is given:



The standard form of a quadratic parabola is

, where (h,k) is the vertex.

Since it is given that the vertex (h,k) = (-2, -20),

h = -2, and k = -20.

And since it passes through the point (0, -12),

x = 0 and y = -12

Substituting in

,















Now go back to the standard form:



Substitute a = 2, h = -2, k = -20

However this time, we do not substitute anything
for x and y, for we want to leave them as variables:





Then we simplify:











Edwin