SOLUTION: I would appreciate any help with this problem. Solve by completing the square 4x^2+2x-3=0

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: I would appreciate any help with this problem. Solve by completing the square 4x^2+2x-3=0      Log On


   

Question 110341: I would appreciate any help with this problem.
Solve by completing the square
4x^2+2x-3=0
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
4x%5E2+%2B+2x+-+3+=+0
divide both sides by 4
x%5E2+%2B%281%2F2%29x+-+%283%2F4%29+=+0
add 3/4 to both sides
x%5E2+%2B+%281%2F2%29x+=+3%2F4
Now take 1/2 of the coefficient of x, square it, and add to both sides
x%5E2+%2B+%281%2F2%29x+%2B+%281%2F16%29+=+%283%2F4%29+%2B+%281%2F16%29
x%5E2+%2B+%281%2F2%29x+%2B+%281%2F16%29+=+13%2F16
%28x+%2B+%281%2F4%29%29%5E2+=+13%2F16
take the square root of both sides
x+%2B+%281%2F4%29+=+%2B+sqrt%2813%2F16%29
x+%2B+%281%2F4%29+=+-+sqrt%2813%2F16%29 both of these are true
solve for x
x+=+-%281%2F4%29+%2B+%28sqrt%2813%29%29%2F4
x+=+%28-1+%2B+sqrt%2813%29%29+%2F+4 answer
and
x+=+-%281%2F4%29+-+%28sqrt%2813%29%29%2F4
x+=+%28-1+-+sqrt%2813%29%29+%2F+4 answer
You can check answers by plugging both (one at a time) into
the original equation. I checked one of them & checked OK