Question 1103213: The Extreme Rock Climbing Club planned a climbing expedition. The total cost was $2000, which was to be divided equally among the members going. Prior to the trip, 5 members decided not to go. If the cost per person increased by $20, how many people went on the expedition?
Found 3 solutions by stanbon, ikleyn, josmiceli:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The Extreme Rock Climbing Club planned a climbing expedition. The total cost was $2000, which was to be divided equally among the members going. Prior to the trip, 5 members decided not to go. If the cost per person increased by $20, how many people went on the expedition?
-----
Original cost per person:: 2000/x
--------------
Changed cost per person:: 2000/(x-5)
---------------------------
Equation:: original - changed = 20
2000/x - 2000/(x-5) = 20
2000x- 2000*5 - 2000x = 20x(x-5)
-10000 = 20x^2-100
----
-500 = x^2 - 10x
------------------
x^2 - 10x + 500 = 0
x = 17.91
-----
Note:: That answer should be a whole number.
-----
Cheers,
Stan H.
-----------
Answer by ikleyn(52777)  (Show Source):
You can put this solution on YOUR website! The Extreme Rock Climbing Club planned a climbing expedition. The total cost was $2000, which was to be divided equally among the members going. Prior to the trip, 5 members decided not to go. If the cost per person increased by $20, how many people went on the expedition?
-----
Original cost per person:: 2000/x
--------------
Changed cost per person:: 2000/(x-5)
---------------------------
Equation:: changed - original = 20
2000/(x-5) - 2000/x = 20
2000x - 2000x + 2000*5 = 20x(x-5)
10000 = 20x^2-100
----
500 = x^2 - 5x
------------------
x^2 - 5x - 500 = 0
(x+20)*(x-25) = 0
-----
Only positive root makes sense ====> x = 25.
-----
SOLVED.
Answer by josmiceli(19441)  (Show Source):
|
|
|
