SOLUTION: From the top of a building, a student throws a ball upward. This function gives the height, h, of the ball in feet after t seconds. h( t )=−16t2+32t+80 What

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: From the top of a building, a student throws a ball upward. This function gives the height, h, of the ball in feet after t seconds. h( t )=−16t2+32t+80 What      Log On


   

Question 1103098: From the top of a building, a student throws a ball upward. This function gives the height, h, of the ball in feet after t seconds.
h( t )=−16t2+32t+80
What is the average rate of change, in feet per second, of the height of the ball from t=0.5 seconds to t=3 seconds?
Answer by ikleyn(52781) About Me  (Show Source):
You can put this solution on YOUR website!
.
The average rate of change, in feet per second, of the height of the ball from t=0.5 seconds to t=3 seconds = %28h%283%29-h%280.5%29%29%2F%283-0.5%29.   (*)


You do not need solving any equation.


You need to calculate the given function h(t) at  t= 3    by substituting "3" instead of t into the formula;

       then calculate the given function h(t) at  t= 0.5  by substituting "0.5" instead of t into the formula;


Then calculate the value (*).

That's all.