SOLUTION: The equation y = -16t^2 - 18t + 405 describes the height (in feet) of a ball thrown downward at 18 feet per second from a height of 405 feet from the ground. In how many seconds wi

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: The equation y = -16t^2 - 18t + 405 describes the height (in feet) of a ball thrown downward at 18 feet per second from a height of 405 feet from the ground. In how many seconds wi      Log On


   



Question 1090463: The equation y = -16t^2 - 18t + 405 describes the height (in feet) of a ball thrown downward at 18 feet per second from a height of 405 feet from the ground. In how many seconds will the ball hit the ground? Express your answer as a decimal rounded to the nearest tenth.
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!

When the ball hits the ground, its height is 0. So you want to solve the equation
-16t%5E2-18t%2B405=0
The question asks for an answer to the nearest tenth, suggesting that the answer is not a "nice" number and has to be rounded. However, the quadratic expression factors, yielding an exact answer.

You could just use the quadratic formula, or perhaps a graphing calculator or some other such tool, to find the answer. But let's instead get some practice with this problem on factoring quadratics.

I would first factor out a -1, so that the leading coefficient is positive; factoring a quadratic with a negative leading coefficient I find to be a very unpleasant task. So our quadratic is
-1%2816t%5E2%2B18t-405%29

With a leading coefficient of 16, the leading coefficients of our two binomial factors could be 1 and 16, or 2 and 8, or 4 and 4.

But in fact they can't be 4 and 4 -- because then the coefficient of the linear (x) term would have to be a multiple of 4, which it is not.

And leading coefficients of 1 and 16 on the binomial factors is unlikely, so I would look first for a factorization with 2 and 8 as the leading coefficients of the two binomial factors.

Some of the possible factorizations of the constant term 405 are 81*5, 27*15, 9*45, .... Some playing around with the different possible combinations shows the factorization to be
16t%5E2%2B18r-405=%288t%2B45%29%282t-9%29

Setting the first factor equal to 0 gives us a negative value for the time t, which does not make sense in the actual problem. Setting the second factor equal to 0 gives us the value of 4.5 for t.

So that is the answer to the problem: the ball hits the ground after 4.5 seconds.