SOLUTION: Find m (m < 0) such that y = mx &#8722; 7 has one intersection point with y = &#8722;m (x + 1)^2 &#8722; 5.

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Find m (m < 0) such that y = mx &#8722; 7 has one intersection point with y = &#8722;m (x + 1)^2 &#8722; 5.       Log On


   

Question 1088372: Find m (m < 0) such that y = mx − 7 has one intersection point with y = −m (x + 1)^2 − 5.

Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
mx-7=-m%28x%2B1%29%5E2-5
-m%28x%5E2%2B2x%2B1%29-5-mx%2B7=0
-mx%5E2-2mx-m-mx%2B2=0
-mx%5E2-3mx-m%2B2=0
mx%5E2%2B3mx%2Bm-2=0

ONE intersection point: %283m%29%5E2-4%2Am%2A%28m-2%29=0
9m%5E2-4m%5E2%2B8m=0
5m%5E2%2B8m=0
m%285m%2B8%29=0,
and because given m%3C0, need to have 5m%2B8=0
5m=-8
highlight%28m=-8%2F5%29.