SOLUTION: Solve the quadratic inequality. Write the solution set in interval notation. Show the complete solution. &#119886;2+3&#119886;+2<&#8722;3(&#119886;+2)

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Solve the quadratic inequality. Write the solution set in interval notation. Show the complete solution. &#119886;2+3&#119886;+2<&#8722;3(&#119886;+2)      Log On


   



Question 1087724: Solve the quadratic inequality. Write the solution set in interval notation. Show the complete solution.
𝑎2+3𝑎+2<−3(𝑎+2)

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
I will write it as
a%5E2%2B3a%2B2%3C-3%28a%2B2%29 , because I am assuming that that is what you meant.

To solve inequalities, we transform them into equivalent inequalities
(meaning inequalities that have exactly all the same solutions).
To do that it is always safe to add the same number or expression to both sides.
In this case, I found that factoring that quadratic polynomial from the start was easier for me.
a%5E2%2B3a%2B2%3C-3%28a%2B2%29
%28a%2B1%29%28a%2B2%29%3C-3%28a%2B2%29
%28a%2B1%29%28a%2B2%29%2B3%28a%2B2%29%3C-3%28a%2B2%29%2B3%28a%2B2%29
%28%28a%2B1%29%2B3%29%28a%2B2%29%3C0
%28a%2B4%29%28a%2B2%29%3C0
That last inequality could also be written as a%5E2%2B6a%2B8%3C0 ,
but that is not needed in this case.
In fact, the factored form makes it easier to see the solution.
You know that the zeros of %28a%2B4%29%28a%2B2%29 are system%28a=-2%2C%22and%22%2Ca=-4%29 ,
and that is where the sign changes for each factor, and for that quadratic polynomial.
In between those two zeros it is negative,
so the solution to %28a%2B4%29%28a%2B2%29%3C0 is
-4%3Ca%3C-2, or highlight%28%22%28+-4+%2C+-2+%29%22%29 .
graph%28300%2C300%2C-8%2C2%2C-4%2C16%2C%28x%2B2%29%28x%2B4%29%29
That the quadratic polynomial is negative between -4 and -2 is obvioumany different ways.
Looking at the quadratic function/expression/polynomial a%5E2%2B6a%2B8 ,
you see that the leading coefficient is that invisible 1%3E0
in the a%5E2 leading term ,
so its graph opens up, and the polynomial is negative between the roots.
It is also obvious because %28a%2B4%29%28a%2B2%29 is 2%2A4=8%3E0 for a=0 ,
and since the polynomial changes sign for multiplicity 1 zeros a=-2, and, a=-4.
that would make it so that
%28a%2B4%29%28a%2B2%29%3E0 for -2%3Ca (including for a=0),
%28a%2B4%29%28a%2B2%29%3C0 for -4%3Ca%3C-2 , and
%28a%2B4%29%28a%2B2%29%3E0 for a%3C-4 .
You could also look at the sign of each factor.