SOLUTION: Find a polynomial function of degree 3 with 3 and 1 as zeros.

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Question 1087297: Find a polynomial function of degree 3 with 3 and 1 as zeros.
Found 2 solutions by Boreal, Alan3354:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
(x-1)(x-3) are two factors. The third can't be complex, because those come in pairs. Therefore, one of the two roots is repeated (a "bounce" on the graph).
(x-1)^2(x-3)=(x^2-2x+1)(x-3)=x^3-5x^2+7x-3
(x-1)(x-3)^2=(x^2-6x+9)(x-1)=x^3-7x^2+3x-9
graph%28300%2C300%2C-10%2C10%2C-10%2C10%2Cx%5E3-5x%5E2%2B7x-3%2Cx%5E3-7x%5E2%2B15x-9%29

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find a polynomial function of degree 3 with 3 and 1 as zeros.
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--> (x-3)*(x-1)*k where k is any linear function of x.